![]() ![]() But with all the new knowledge I feel I'm getting closer to the solution at last. I feel like I thought it through a million times, but every time I feel sure about something a new aspect kicks in and I'm starting all over. It captures a rectilinear picture as in your - Bradrobb: I wouldn't make such an affort but I wouldn't be able to return the equipment if things don't work as I thought they would. That would have meant that the vertical hight of the sensor is the crucial measurement. In my graphic I placed it in the full frame sensor size because I assumend the lens would capture a full 180°x180° circle view. So does this mean I'm gaining some degrees at the top - bottom Bill - bclaff: The camera has a ribcage to be able to mount MFT lenses. The micro four thirds sensor has a 4:3 aspect ratio while the sensor of the camera I 'm looking at has a 3:2 ratio. So this means that probably there will be even more degrees lost. But the fish eye doesn't record every degree evenly spread over the lens, right? It looks like this: But it's the diagonal FoV, right? So from top to bottom and left to right the angle is gonna be smaller?Īssuming that my cameras sensor is 0.74 times smaller than the micro four thirds sensor, a 132° FoV would be achieved. is right and the 180° Field of View or Angle of View is actually meant for a mirco four thirds sensor. But during the last days I did a lot more research and I found - Marc9473. When I posted my question I assumed that the 180° can be reached with the 7.5 focal length of the lens on a full frame sensor because from what I read thats the standardized way to define it. The formula on the webite for calculating that was:įOV (stereographic fisheye) = 4 * arctan (frame size/(focal length * 4)) Wow - thank you so much for your efforts!! Your thoughts on this topic are very interesting and it helps me a Bill - bclaff: I found out that the lens has a stereographic projection. Yellow circle is the 180 degree MFT image circle red is the MFT sensor blue is the 1" sensor Not sure why you placed the 180 degree circle inside a full frame rectangle Thank you for any helpful thoughts on this! But I'm not sure about the whole thing and also not whether the fisheye shaped lens causes any difference in terms of the calculation? Because the distorion gets more towards the edges? I attached a little graphic below to visualize my results. But the camera I've chosen has a special mounting system which increases the crop factor to 2,79.ĭoes this calculation seem reasonable to you and does that mean that the actual focal length is ~20,9 mm?Īnd - even more important - what does that mean for the FoV of this camera-lens combination? How many degrees will be left? Knowing this I assume the crop factor would be 2,70. So I'm hoping someone can confirm (or proof me (Affiliate) wrong with) what I figured up. It's essential to be sure about the FoV before buying the camera and lens combination. Changing the formula to TAN(HFOV/degrees(2)) solved the problem.I ve been doing some research on how to calculate the FoV with a fisheye lens. My problem in Excel was that when I was dividing by 2 in my TAN(HFOV/2), the 2 was in Radians and not degrees. equation would be to allow me to properly calculate the vertical and horizontal FOVs (in mm). I'm looking to understand where my calculations may be going wrong and what a standard and accepted trig. Horizontal FOV (mm) = Working Distance (mm) * 2 * TAN(Horizontal FOV (degrees) / 2) My problem is that the equation above gives me a different value than the following equation: The Horizontal FOV is also in mm, for which I calculate for. Where h is the horizontal sensor dimension, f is the focal length of the lens, and WD is the working distance. I do have values for the following parameters:Įdmund Scientific offered the following equation: 89°, vertical FOV: 46°, diagonal FOV: 105° 6 mm, horizontal FOV: 54°, vertical FOV: 30°, diagonal FOV: 62° Aperture F1.0 Lens Mount M16 Illuminator White Light Range 30 m Video Max. I am having some trouble finding a standard way to calculate the horizontal and vertical field of view of an image based on a set of initial input parameters. 4 MP ColorVu Fixed Bullet Network Camera 1/1.8' Progressive Scan CMOS 2560 × 1440 25fps F1.0 aperture, 2.8/4/6 mm. ![]()
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